Daniel had 25 to spend at the fair if the admission to the fair to s 4 and the rides cost 1.50 each write an inequality that represent Daniels situation

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02-02-2020
Mathematics

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Daniel had 25 to spend at the fair if the admission to the fair to s 4 and the rides cost 1.50 each write an inequality that represent Daniels situation

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iwillanswer iwillanswer · Answer 1 · 2020-02-08T07:36:09+01:00

Question:

Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, write an inequality that represent Daniels situation what is the greatest number of rides daniel can go on?

Answer:

The inequality that represents Daniel situation is:

[tex]4 + 1.50x\leq 25[/tex]

The greatest number of rides Daniel can go is 14

Solution:

Daniel had $25 to spend at the fair

Total amount with Daniel = $ 25

Admission price = $ 4

Cost of 1 ride = $ 1.50

Let "x" be the number of rides

Then cost of "x" rides is 1.50x

Then, we frame a inequality as:

Admission price + cost of "x" ride [tex]\leq[/tex] 25

[tex]4 + 1.50x\leq 25[/tex]

Here we used "less than or equal to" symbol, because he can spend maximum upto 25 dollars

Solve for "x"

[tex]4 + 1.50x\leq 25\\\\1.50x \leq 25 -4\\\\1.50x\leq 21\\\\Divide\ both\ sides\ by\ 1.50\\\\x\leq 14[/tex]

Thus greatest number of rides is 14