The amount of heat lost by the water is 1870 calories
Step-by-step explanation:
The amount of heat released by a substance is given by the equation
[tex]Q=mC\Delta T[/tex]
where
Q is the amount of heat lost
m is the mass of the substance
C is the specific heat capacity of the substance
[tex]\Delta T[/tex] is its change in temperature
In this problem, we have:
m = 85 g is the mass of water
[tex]C=1 cal /g^{\circ}C[/tex] is the specific heat capacity of water
[tex]\Delta T = 23-45=-22^{\circ}C[/tex] is the change in temperature of the water
Substituting, we find
[tex]Q=(85)(1)(-22)=-1870 cal[/tex]
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