Answer:
Step-by-step explanation:
The equation can be rewritten to vertex form to find the maximum value:
I = -5(t^2 -2t) +2 . . . . . . factor leading coefficient from variable terms
I = -5(t^2 -2t +1) +2 -(-5(1)) . . . . . add and subtract the square of half the t coefficient
I = -5(t -1)^2 +7 . . . . . . write in vertex form
The vertex of the graph is at (t, I) = (1, 7).
The maximum current of 7 is reached at t=1.
Answer:
Step-by-step explanation:
The current I in a device is related to time t by the equation
I = 10t - 5t² + 2
The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum current in the device
The vertex of the parabola is calculated as follows,
Vertex = -b/2a
From the equation,
a = - 5
b = 10
Vertex = - 10/2 × - 5 = - 10/ - 10 = 1
Therefore, the time taken to reach maximum current is 1
The maximum current would be
I = (10 × 1)- (5 × 1²) + 2
I = 10- 5 + 2 = 7
