Answer:
the number of combinations is always less than the number of permutations
Step-by-step explanation:
Without considering numbers , the number of combinations is always less than the number of permutations since the permutations consider the different arrangements of the elements for given set of numbers taken as different permutations, while the combination only takes one arrangement for any given set of numbers taken.
Mathematically
permutations of 10 elements taken six at a time= A( 10 ,6) = 10!/6!
combinations of 10 elements taken six at a time = C ( 10 ,6) = 10!/[6! * (10-6)!] = 10!/[ 6! * 4! ] = A/4!
since 4!>1 then C<A
