Respuesta :
Explanation:
It is known that relation between heat energy, mass and temperature change is as follows.
q = [tex]mC \times \Delta T[/tex]
where, C = specific heat of water (in given case) = 4.184 [tex]kJ/kg ^{o}C[/tex]
m = mass
[tex]\Delta T[/tex] = change in temperature
Therefore, calculate the heat energy as follows.
q = [tex]mC \times \Delta T[/tex]
= [tex]4 kg \times 4.184 kJ/kg^{o}C \times (100 - 25)^{o}C[/tex]
= 1255.2 kJ/day
For 10 days, total heat required is as follows.
[tex]10 \times 1255.2[/tex]
= 12552 kJ
It is known that the value of standard enthalpy of combustion of butane is -49.5 kJ/g.
Therefore, combustion of 1 gm of butane will be 49.5 kJ. Hence, total amount of butane required will be as follows.
[tex]\frac{12552 kJ}{49.5 kJ/g}[/tex]
= 253.57 g
As it is given that 1 canister of butane contains 75 g butane. Hence, no. of canisters required are as follows.
No. of canisters required = [tex]\frac{253.57}{75}[/tex]
= 3.38
= 4 (approximately)
Thus, we can conclude that minimum number of fuel canisters you must bring are 4.
