Answer:
The pressure difference between points 1 and 2 is 0.19119 psi.
Explanation:
Given that,
Density of manometer fluid = 6.75 g/cm³
Height of side 1[tex]H= 2.80\times10^{2}\ mm[/tex]
Height of side 2= 309 mm
We need to calculate the pressure difference between points 1 and 2
Using balancing pressure at height 1 and 2
[tex]P_{1}+\rho_{w} g(H_{2}-H_{1})=P_{2}+\rho_{l}g(H_{2}-H_{1})[/tex]
[tex]P_{2}-P_{1}=\rho_{l}g(H_{2}-H_{1})-\rho_{w}g(H_{2}-H_{1})[/tex]
[tex]P_{2}-P_{1}=g(H_{2}-H_{1})(\rho_{l}-\rho_{w})[/tex]
[tex]P_{2}-P_{1}=9.8(0.309-0.00280\times102)(6750-1000)[/tex]
[tex]P_{2}-P_{1}=1318.59\ Pa[/tex]
[tex]\Delta P=1318.59\ Pa[/tex]
[tex]\Delta P=1318.59\times0.000145[/tex]
[tex]\Delta P=0.19119\ psi[/tex]
Hence, The pressure difference between points 1 and 2 is 0.19119 psi.
