Answer:
C. 0.05 J
Explanation:
Given that
Spring constant ,K= 10 N/m
Distance ,x = 0.1 m
The amplitude ,A= 0.1 m
The stored energy potential energy in the spring
[tex]U=\dfrac{1}{2}KA^2[/tex]
Now by putting the values
[tex]U=\dfrac{1}{2}\times 10\times 0.1^2\ J[/tex]
U=0.05 J
Now From energy conservation
The maximum kinetic energy = The Maximum potential energy
KE= U
KE= 0.05 J
Therefore the answer will be C.
C. 0.05 J
