Answer:
4.5 m.
Explanation:
Using newton's equation of motion,
S = (u+v)t/2...................... Equation 1
Where S = distance covered by the basket ball player, u = initial velocity of the basket ball payer, v = final velocity of the basket ball player, t = time.
Note: The basket starts from rest, as such the initial velocity = 0 m/s
Given: u = 0 m/s ( from rest), v = 6 m/s, t = 1.5 s.
Substitute into equation 1
S = (6+0)1.5/2
S = 9/2
S = 4.5 m.
Hence the distance covered by the basket ball player = 4.5 m.
