Answer:
The three consecutive even integers are
[tex]x=-10\\x+2=-8\\x+4=-6[/tex]
Step-by-step explanation:
Let
x ----> the smallest of three consecutive even integers
x+2 ----> the second consecutive even integers
x+4 ----> the largest of three consecutive even integers
we know that
Three times the largest of three consecutive even integers is equal to the sum of the other two
so
[tex]3(x+4)=x+(x+2)[/tex]
solve for x
[tex]3x+12=2x+2\\3x-2x=2-12\\x=-10[/tex]
Find (x+2)
[tex](x+2)=-10+2=-8[/tex]
Find (x+4)
[tex](x+4)=-10+4=-6[/tex]
therefore
The three consecutive even integers are
[tex]x=-10\\x+2=-8\\x+4=-6[/tex]
