contestada

What is the equation in standard form of the line that passes through the point 10,-3 and has a slope of 1/5

Respuesta :

Answer: [tex]5y - x = -25[/tex]

Step-by-step explanation:

The formula for calculating equation of line when a point and a slope is gives is :

[tex]y - y_{1} = m ( x - x_{1})[/tex]

[tex]x_{1} = 10[/tex]

[tex]y_{1} = -3[/tex]

[tex]m = \frac{1}{5}[/tex]

substituting into the formula , we have

[tex]y - (-3) = \frac{1}{5}(x - 10 )[/tex]

[tex]y + 3 = \frac{1}{5}(x - 10 )[/tex]

multiply through by 5 ,

[tex]5 (y+ 3 ) = x - 10[/tex]

[tex]5y + 15 = x - 10[/tex]

in standard from , we have

[tex]5y - x = -10 - 15[/tex]

[tex]5y - x = -25[/tex]