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A slab of a thermal insulator is 100 cm2 in cross section and 2 cm thick. Its thermal conductivity is 0.1 J/s.m.ºC. If the temperature difference between opposite faces is 100 ºC, how much heat flows through the slab in one day?

Respuesta :

-5 W is the heat flows through the slab in one day

Explanation:

  • The heat transferred is directly proportional to the area of the material and the temperature differences in the body, whereas the heat transfer is inversely proportional to the length of the material
  • The equation can be written as  [tex]Q=-k \frac{ A T}{l}[/tex] where Q is the heat transfer, k is the thermal conductivity of the material, A is the area of the material and T is the difference in the temperature and the l is  the length of the material.
  • Given that, A= 100 [tex]cm^{2}[/tex] , l= 2 cm, k = 0.1 J/S. m. c and T= 100 degree Celsius
  • Substitute these values in the equation, you will get Q= -5 W

The heat flow through the slab in one day is of 5 J.

Thermal Insulation:

The phenomenon by which the heat flow from one point to another is restricted through a specific material (insulators), is known as thermal insulation.

Given data:

The area of the thermal insulator is, A = 100 cm² = 0.01 m².

The thickness of the insulator is, t = 2 cm = 0.02 m.

The value of thermal conductivity is, k = 0.1 J/s.m.ºC.

The temperature difference between the opposite faces is, ΔT =100°C.

The expression for the heat flow through the insulated slab is,

[tex]Q = \dfrac{k \times A \times \Delta T}{t}[/tex]

Solving as

[tex]Q = \dfrac{0.1 \times (0.01) \times 100}{0.02}\\\\ Q = 5 \;\rm J[/tex]

Thus, we can conclude that the heat flow through the slab in one day is of 5 J.

Learn more about the thermal conductivity here:

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