Answer:
the phase difference is 1.26 radian
Solution:
As per the question:
Distance, d = 2 m
Distance from the other speaker, d' = 2.1 m
Frequency, f = 680 Hz
Speed of sound, v = 340 m/s
Now,
To calculate the phase difference, [tex]\Delta \phi[/tex]:
Path difference, [tex]\Delta d = d' - d = 2.1 - 2 = 0.1\ m[/tex]
For the wavelength:
[tex]f\lambda = v[/tex]
where
c = speed of light in vacuum
[tex]\lambda [/tex] = wavelength
Now,
[tex]680\times \lambda = 340[/tex]
[tex]\lambda = 0.5\ m[/tex]
Now,
Phase difference, [tex]\Delta phi = 2\pi \frac{\Delta d}{\lambda}[/tex]
[tex]\Delta phi = 2\pi \frac{0.1}{0.5} = 1.26\ rad[/tex]
