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A charge +1.9 μC is placed at the center of the hollow spherical conductor with the inner radius 3.8 cm and outer radius 5.6 cm. Suppose the conductor initially has a net charge of +3.8 μC instead of being neutral. What is the total charge (a) on the interior and (b) on the exterior surface?

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cjmejiab

To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.

PART A)

The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:

[tex]Q_{int}=-Q1=-1.9*10^{-6} C[/tex]. This is the total charge on the inner surface of the conducting shell.

PART B)

The positive charge (of the same value) on the external surface of the conducting shell is:

[tex]Q_{ext}=+Q_1=1.9*10^{-6} C[/tex]

The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,

[tex]Q_{ext, Total}=Q_2+Q_{ext}[/tex]

[tex]Q_{ext, Total}=1.9+3.8[/tex]

[tex]Q_{ext, Total}=5.7 \mu C[/tex]

onyebuchinnaji

(a) The total charge on the interior of the spherical conductor is -1.9 μC.

(b) The total exterior charge of the spherical conductor is 5.7 μC.

The given parameters;

  • charge at the center of the hollow sphere, q = 1.9 μC
  • inner radius of the spherical conductor, r₁ = 3.8 cm
  • outer radius of the spherical conductor, r₂ = 5.6 cm

The total charge on the interior is calculated as follows;

[tex]Q_{int} = - 1.9 \ \mu C[/tex]

The total exterior charge is calculated as follows;

[tex]Q_{tot . \ ext} = Q + Q_2\\\\Q_{tot . \ ext} = 1.9 \ \mu C \ + \ 3.8 \ \mu C\\\\Q_{tot . \ ext} = 5.7 \ \mu C[/tex]

Learn more about total charge on hollow spherical conductor here: https://brainly.com/question/14909974

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