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a car moving 50 miles per he speeds up steadily to 70 miles per he over a period of 30 minutes.how far did it travel during the 30 minute period of acceleration?

Respuesta :

The acceleration of the car is 70 miles per hour per 30 minutes or equal to 140 miles/h². Given the initial speed (v1), the acceleration (a), and the time (t), the distance traveled is calculated by,
                                   d = (v1)(t) + 0.5(a)(t²)
Substituting the given values,
                 d = (50 miles/h) x (0.5 h) + (0.5)(140 miles/h²)(0.5 h)² = 42.5
Thus, the car traveled about 42.5 miles. 

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