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A scientist is observing the grizzly bear population in two state parks. The parks each have 150 bears when he begins observing them. The population in Park A increases by 20% each year. The population in Park B decreases by 20% each year. In each equation, y represents the bear population with respect to a number of years, x. Drag each equation to show whether it can be used to represent the bear population in Park A, Park B, or neither of these.

Please help meA scientist is observing the grizzly bear population in two state parks The parks each have 150 bears when he begins observing them The population class=

Respuesta :

Park A

Y=150(6/5)ˣ

Y=150(1+0.20)ˣ

Park B

Y=150(4/5)ˣ

Y=150(1-0.20)ˣ

Neither of these

Y=6/5.(150)ˣ

Y=4/5.(150)ˣ

Step-by-step explanation:

As given in the question, the population of bear

  • increases year after year
  • decreases yearly

⇔It means the given actions are compounding in fashion

We know that for Compound Increase/Decrease  

Y=X(1+R/100)ⁿ

Where  

Y= final number after intended “n” time

X=Initial number at the starting

R= Rate of compounding

ⁿ= period into consideration

FOR PARK A

Since the bear population increases by 20% per annum

Y= 150(1+20/100)ˣ

⇒Y=150(1+0.20)ˣ

similarly

Y=150(1+1/5)ˣ  (reducing the fraction 20/100)

⇒Y=150(6/5)ˣ

Where Y= population of the bear after x years

X= years

Initial population of bear =150(given)

FOR PARK B

Since the bear population decreases by 20% per annum

Y= 150(1-20/100)ˣ

⇒Y=150(1-0.20)ˣ

similarly

Y=150(1-1/5)ˣ (reducing the fraction 20/100)

⇒Y=150(4/5)ˣ

The remaining of the function would group under none of these

Answer:

Park A

Y=150(6/5)ˣ

Y=150(1+0.20)ˣ

Park B

Y=150(4/5)ˣ

Y=150(1-0.20)ˣ

Neither of these

Y=6/5.(150)ˣ

Y=4/5.(150)ˣ

Step-by-step explanation:

i Took the test

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