0.9+{[3.25−(6 9/16 −0.025y)·0.6]÷0.75}÷6 2/3 =1.2 solve for y
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Respuesta :

Answer:

[tex]y = \dfrac{875}{6}[/tex]

Step-by-step explanation:

We use the PEMDAS rule, meaning the order of priority is parenthesis, Multiplication, Division, Addition, and Subtraction.

With PEMDAS, let us simply the equation

[tex]0.9+[[3.25-(6+9/16-0.025y)*0.6]\div 0.75] \div 6 \dfrac{2}{3} =1.2[/tex]

First let us simplify the parenthesis [tex]()[/tex] and get:

[tex]0.9+[[3.25-(6.5625-0.025y)*0.6]\div 0.75] \div 6 \dfrac{2}{3} =1.2[/tex]

and multiply what is in [tex]()[/tex] by [tex]-1[/tex] and  [tex]0.6[/tex] to get:

[tex]0.9+[[3.25-3.9375+0.015y]\div 0.75] \div 6 \dfrac{2}{3} =1.2[/tex]

[tex]0.9+[[-0.6875+0.015y]\div 0.75] \div 6 \dfrac{2}{3} =1.2[/tex]

Now we divide what is in [tex][][/tex] by 0.75 to get:

[tex]0.9+[-0.91667+0.02y] \div 6 \dfrac{2}{3} =1.2[/tex]

and we divide [tex][][/tex] by [tex]6 \dfrac{2}{3}[/tex]  and get:

[tex]0.9-\dfrac{11}{80} +\dfrac{3}{1000}y =1.2[/tex]

simplifying gives us

[tex]\dfrac{61}{80} +\dfrac{3}{1000}y =1.2[/tex]

[tex]\dfrac{3}{100}y =\dfrac{7}{16}[/tex]

[tex]\boxed{y = \dfrac{875}{6} }[/tex]