Answer:
3.69 V
Explanation:
By connecting across the resistor, the capacitor starts discharging.
The voltage across the capacitor when discharging is given by
[tex]V = V_0e^{-t/T}[/tex]
V is the voltage across it at time t,
[tex]V_0[/tex] is the initial voltage when fully charged,
T is the time constant
After one time constant, t = T. Then
[tex]V = V_0e^{-T/T}= 0.369V_0[/tex]
From the question, [tex]V_0 =10 \text{ V}[/tex]
[tex]V = 10\text{ V}\times0.369 = 3.69 \text{ V}[/tex]
