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the point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = -2/5 (x – 10). what is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x 5y = –15 2x 5y = –17

Respuesta :

Ckaranja
Gradient, m=[tex] \frac{-1--7}{-5-10} [/tex]
m=[tex] \frac{6}{-15} = \frac{-2}{5} [/tex]
Standard form then is;
y=[tex] \frac{-2}{5} x+c[/tex]

Finding value of c using point (-5,-1);
-1=[tex] \frac{-2}{5} *(-5)[/tex]+c
-1=2+c
c=-3
y=[tex] \frac{-2}{5} x-3[/tex]

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