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Two blocks with masses M1 and M2 hang one under the other.
For this problem, take the positive direction to be upward, and use g for the magnitude of the acceleration due to gravity.
Blocks at rest For Parts (a) and (b) assume the blocks are at rest.
(a) Find T2, the tension in the lower rope. Express your answer in terms of some or all of the variables M1, M2, and g.
(b) Find T1, the tension in the upper rope. Express your answer in terms of some or all of the variables M1, M2, and g.
For Parts (c) and (d) the blocks are now accelerating upward (due to the tension in the strings) with an acceleration of magnitude a.
(c) Find T2, the tension in the lower rope. Express your answer in terms of some or all of the variables M1, M2, and g.
(d) Find T1, the tension in the upper rope. Express your answer in terms of some or all of the variablesM1, M2, a and g.

Respuesta :

muhammadjonedkhattak

Answer:

(a)T= M2 × g,    (b)T= (M1 + M2)g,   (c)T= M2 (a + g) and  (d)T=(M1 + M2) (a + g)

Explanation:

M1 is hanged upper and M2 is lower at Rest.

(a) For M2

T2 = Weight of the Body M2= M2 × g

(b) T1 = Weight of the Body M2 + Weight of the Body M2

T1 = M1 g + M2 g = (M1 + M2)g

M1 is hanged upper and M2 is lower at accelerated upwards ( F = T - W)

(c) For M2

⇒T = M2a + M2g = M2 (a + g)

(d) For M1

T = (M1 + M2) a + (M1 + M2) g

⇒ T = (M1 + M2) (a + g)

Ver imagen muhammadjonedkhattak
abidemiokin
  • The expression of T2 in terms of other variables is T2 = M2g
  • The tension T1 is acting on the mass M1 and mass M2 is expressed as T1 = (M1+M2)g
  • The mass M2 of the object is expressed as M2 = T/(a+g)
  • The mass M1 in the upper rope is expressed as M1 = (T/a+g) - M2

The formula for calculating the weight W of an object with mass m is expressed as;

W = mg

m is the mass of the object

g is the acceleration due to gravity

For the mass M2, the tension acting on the body is expressed according to the formula:

T2 = M2g

b) The tension T1 is acting on the mass M1 and mass M2. Hence the formula for calculating the tension T1 will be:

T1 = M1g + M2g

T1 = (M1+M2)g

c) For mass M2, first we must know that acceleration due to M2 are the normal acceleration and acceleration due to gravity. The tension T acting on both object will be:

T = (M2a + M2g)

T = M2(a + g)

M2 = T/(a+g)

d) For the mass M1, the correct relationship will be expressed as;

T = M1a + M2a + M1g + M2g

T = (M1+M2)a + (M1+M2)g

Since M1+M2 is common,

T = M1+M2(a+g)

T/a+g = M1+M2

M1 = (T/a+g) - M2

Learn more here: brainly.com/questions/35542778

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