Answer:
See explanation
Step-by-step explanation:
Given the function f(x) for which
[tex]\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}[/tex]
If you want to plot the corresponding points for the inverse of the function f(x), change [tex]f(x)[/tex] into [tex]y[/tex]:
[tex]\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}[/tex]
switch x and y
[tex]\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}[/tex]
and then change [tex]y[/tex] into [tex]f^{-1}(x).[/tex]
You get
[tex]\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}[/tex]
Now plot these points on the coordinate plane (see attached diagram).
