Answer:
The percentage of mass of nitrogen in ammonium sulfate is 21.20%
Explanation:
Solving this problem, we need to know that nitrogen is a gas and also we need to calculate the molar mass of the compound which (NH4)2SO4
Mm of (NH4)2SO4 =
N - 14.0067
H - 1.00784
S - 32.065
O - 15.999
Mm = (14.0067)2+(1.00784*4)2+32.065+(15.999*4)
Note: Because there are 4*2=8atoms of hydrogen and 4 atoms of oxygen and 2 atoms of nitrogen in the compound
Mm = 28.0134+ 8.06272+32.065+63.996
= 132.13712g/mol
Since there are two atoms of nitrogen in ammonium sulfate
The mm of N = 2 * 14.0067
= 28.0134g/mol
Therefore, to calculate percent massof N in (NH4)2SO4
We divide the mm of N by mm of (NH4)2SO4 multiplied by 100
i. e. 28.0134/132.14
= 0.212
= 0.212 * 100
= 21.20% mass of nitrogen
