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You play racquetball at a community club. You have two options for paying for court time. Option A: You pay $12 for court time each time you play. Option B: You buy a club membership for $120 and then pay $2 each time you play. a. Write and solve a linear system to determine the number of visits for which the cost would be the same for each option. b. For what numbers of visits is option B less expensive

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temdan2001

Answer: y = 12x

Y = 2x + 120

a). X = 12

b). X= 14

Explanation: for the two options cost to be the same, you equate the two equations.

For the visit of option B to be less expensive, X will be greater than 12

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Answer:

a) The answer is 12 visits (b) number of visits greater than 12

Explanation:

Option A = $12 per visit

Option B = $120 for membership $2 for each time you play

We have to equate the two options to get a linear system

Let each visit be x

A = 12x

B = 120 + 2x

equating A and B

12x = 120 + 2x

120= 10x

x = 12.  The answer is 12 visits

b) the number of visits for option b is less expensive is any visit greater than the equilibrium cost for both options. example if I visit for a 13th time then

option A = 12 X 13 = 156

option B = 120 + 2(13) = 146

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