Answer:
108 Watts
Explanation:
The total circuit resistance when the resistors are connected in series is
R + R + R = 3R
When he resistors are connected in parallel, the resistance reduces from 3R in the series circuit to become;
[tex]\frac{1}{R} + \frac{1}{R} + \frac{1}{R}[/tex]
= [tex]\frac{R}{3}[/tex] Ω
[tex]Power = \frac{V^{2}}{R}[/tex]
The voltage supply was given to be constant for both the series and parallel circuits. This implies that V² is constant and power is inversely proportional to resistance.
Therefore;
Power for the parallel connected circuit = [tex]\frac{3R}{\frac{R}{3} } * 12 W[/tex]
= 9 × 12 W = 108 Watts
Answer:
Explanation:
Potential difference, V and let each resistance, R
Resistors are in series, total resistance, Rₓ = R1 + R2 + R3
= R + R + R
= 3R
Power, P = V²/Rₓ
12 = V²/3R
V²/R = 36
Resistors are in parallel, total resistance, 1/Rₓ = 1/R1 + 1/R2 + 1/R3
Rₓ = R/3
P = V²/Rₓ
P = V²/(R/3)
P = 3(V²/R)
= 3(36)
= 108 W.
