The mean of the top five test scores is 96. Then the mean absolute deviation is zero.
What is the mean absolute deviation?
It is the average distance between each data point and the mean.
The top five test scores in Mr. Rhodes's class were: 98, 92, 96, 97, and 97.
Then the mean (μ) will be
[tex]\mu = \dfrac{98+92+96+97+97}{5}\\\\\mu = \dfrac{480}{5}\\\\\mu = 96[/tex]
Then the mean absolute deviation will be
[tex]\rm MAD = \dfrac{\Sigma (X_i - \mu)}{n}\\\\MAD = \dfrac{(98-96)+(92-96)+(96-96)+(97-96)+(97-96)}{5}\\\\MAD = \dfrac{2-4+0+1+1}{5}\\\\MAD = 0[/tex]
The mean absolute deviation is zero and the mean is 96.
More about the mean absolute deviation link is given below.
https://brainly.com/question/10258446
