20 POINTS WILL MARK BRAINLIEST

Every morning, siblings Jack and Jill roll a regular six-sided die to determine who will get to ride in the front seat on the way to school. If the number is even, Jack gets to ride in the front. If the number is odd, Jill gets to ride in the front.

A. In the first 20 school days, how many times would you expect Jack to get to ride in the front seat?
B. In the first 100 school days, how many times would you expect Jill to get to ride in the front seat?
C. Which prediction (Jack or Jill's) do you think will be closer to the actual frequency? Use complete sentences to justify your answer.

Respuesta :

PHG

Answer:

Step-by-step explanation:

A.  It says he will get to sit in the front if the number is even

There are 6 sides, three of which are even numbers (2,4,6). So the probability of rolling an even number is 3/6 = 1/2.

Let's make p = 1/2

Jack will get his way half of the time, so we expect him to get the front seat half of the time

If we're talking about 20 days, then n = 20 and

n*p = 20*(1/2) = 20/2 = 10

meaning that Jack would, on average, get the front seat 10 times out of the 20 total.

B. Similar to A

n=100

The probability is still the same because rolling an odd number (1,3,5) is still going to happen 3/6 = 1/2 of the time.

so: n*p means 100 days*1/2 which is 100/2=50 days

Jill get to sit in the front 50 out of the 100 days.

C. For better accuracy, we can at least increase the number of trials so we have more data in able for better accuracy.

As Jill did 100 hundred, we think that she will get closer to the actual frequency. As larger the number of trials, the closer we'll get to the expected probability.

Answer:

A. Jack to get to ride in the front seat 10 times

B. In the first 100 school days, Jill will get to ride in the front seat 50 times.

C. As Jill did 100, I think that she will get closer to the actual frequency. As larger the number of trials, the closer we'll get to the expected probability.

Step-by-step explanation: