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A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.
Click "Show Your Work" and write a quadratic function, h(t), that shows
the height, in feet, of the soccer ball, t seconds after it was kicked. Use
the general equation h(t) = -16t2 + v0t + h0 where v0 is the initial velocity
and h0 is the initial height.
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Respuesta :

Answer:

h(t) = - 16t² + 96t

Step-by-step explanation:

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

So, it initial height, [tex]h_0 = 0[/tex] ft. and initial velocity [tex]v_0 = 96[/tex] feet/sec.

Now, the quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked will be given by the general equation

[tex]h(t) = - 16t^{2} + v_0t + h_0[/tex]

⇒ h(t) = - 16t² + 96t + 0

⇒ h(t) = - 16t² + 96t (Answer)

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