Respuesta :
Answer:
Wavelength = 1.12 μm
Explanation:
Fringe width = Distance between consecutive maximums or consecutive minimums
Using the first bright fringe to calculate the wavelength
The first bright fringe, [tex]\beta = 3 cm = 3/100 = 0.03 m[/tex]
Distance between the laser and the ruler, [tex]L_{1} = 12.3 m[/tex]
Distance between the laser and the slits, [tex]L_{2} = 0.511 m[/tex]
Distance between the ruler and the slits, [tex]D = L_{1} - L_{2}[/tex]
[tex]D = 12.3 - 0.511[/tex]
[tex]D = 11.789 m[/tex]
distance, d = 0.440 mm = 0.00044 m
The relationship between the fringe width and the wavelength is given by:
The fringe width, [tex]\beta = \frac{\lambda D}{d}[/tex]
[tex]0.03 = \frac{\lambda 11.789}{0.00044} \\0.03 * 0.00044 = \lambda 11.789\\\lambda = \frac{0.03*0.00044}{11.789} \\\lambda = 1.12 * 10^{-6} m \\\lambda = 1.12 \mu m[/tex]
The wavelength when The illustration is not to scale should be considered as the 1.12 μm.
Calculation of the wavelength:
Since
The first bright fringe should be = 3c, = 3/100 = 0.03 m
The horizontal distance L1 between the laser and the ruler is 12.3 m.
The distance L2 between the laser and the slits is 0.511 m.
So, the distance between should be
= 12.3 - 0.511
= 11.789 m
Also,
distance d = 0.440 mm = 0.00044 m
Now the wavelength should be
= 0.03*0.0044/11.789
= 1.12*10^-6 m
= 1.12 μm
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