If the pressure exerted on a 268 mL sample of hydrogen gas at a constant temperature is increased from 0.6 atm to 0.8 atm, what will be the final volume of the sample?

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Respuesta :

Answer: 201 mL

Explanation:

Initial volume V1 = 268 mL

Initial pressure P1 = 0.6 atm

Final volume of the gas V2 = ?

Final pressure of the gas P2 = 0.8 atm

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

0.6 atm x 268 mL = 0.8 atm x V2

160.8 atm mL = 0.8 atm x V2

V2 = (160.8 atm mL / 0.8 atm)

V2 = 201 mL

Thus, the final volume of the hydrogen gas will be 201 mL