Answer:
The value of Discriminant is 0.
Step-by-step explanation:
Given,
[tex]f(x)=-4x^2+12x-9[/tex]
We need to find the value of discriminant.
And also we need to find the number of real zeros 'f(x)' have.
Solution,
We have given the quadratic equation;
[tex]f(x)=-4x^2+12x-9[/tex]
where
[tex]a = -4\\\\b = 10\\\\c = -8[/tex]
Now we will find the Discriminant.
Discriminant can be calculated by using the formula [tex]b^2 - 4ac[/tex].
Substituting the values we get;
[tex]D=b^2 - 4ac = 12^2-4\times(-4)\times(-9)=144-144 =0[/tex]
Hence the value of Discriminant is 0.
