Respuesta :

Length is 8 m and width is 4 m.

Step-by-step explanation:

Given,

The area of the rectangular table = 35 sq m

Sum of its dimensions = 12 m

To find the length and width of the table.

Let, the length and width of the table is l and b respectively.

As per the problem,

lb = 35 and l+b = 12

Formula

(a-b)² = (a+b)²-4ab

Now,

(l-b)² = (l+b)²-4lb

= (12)²-4×35 = 4

so, (l-b) = 2

Now we will solve l+b = 12 and l-b = 4

By adding we get,

l+b+l-b = 12+4

or, 2l = 16

or, l = 8

And b= 12-l = 12-8 = 4

Hence,

Length is 8 m and width is 4 m.

The dimensions are 5 inches and 7 inches.

Let, length = x and width = y.

According to the question:

Area = xy = 35

x + y = 12

or, y = 12 - x.

Plug y = 12 - x in xy = 35.

[tex]xy = 35\\ x(12-x) = 35\\ 12x-x^2=35\\ x^2-12x+35=0\\ (x-5)(x-7)=0\\ x=5,7[/tex]

Hence the dimensions are 5 inches and 7 inches.

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