Answer:
16.5 units
Step-by-step explanation:
The midsegment is the distance between the midpoints of the nonparallel sides of the trapezoid.
The trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10).
We want to find the midsegment of ABCD to the nearest tenth.
The midpoint of BC is;
[tex]( \frac{ - 2 + - 10}{2} , \frac{6 + - 10}{2} ) = ( - 6, - 2)[/tex]
The midpoint of AD is :
[tex]( \frac{1 + 20}{2} , \frac{6 + - 10}{2} ) = ( 10.5, - 2)[/tex]
The length of the midsegment is the distance from (-6,2) to (10.5,2)
[tex] = |10 .5 - - 6| = 16.5[/tex]
