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Find the equation of the linear function h that has h(12)=-7 and that is perpendicular to q(a)=1/2a+38.. I don’t understand how to get the equation and how to write it into slope intercept form

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MathPhys

Step-by-step explanation:

q(a) = ½a + 38

The slope of q is ½.  So the perpendicular slope is -1/½ = -2.

Write h(x) in point-slope form:

h − (-7) = -2 (x − 12)

h + 7 = -2 (x − 12)

Simplify to get slope-intercept form.

h + 7 = -2x + 24

h = -2x + 17

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