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Write the standard equation of a circle with center (−9, −4) and radius square root of 5 .

(x – 4)2 + (y – 9)2 = 5

(x – 9)2 + (y – 4)2 = 5

(x + 4)2 + (y + 9)2 = 5

(x + 9)2 + (y + 4)2 = 5

Write the standard equation of a circle with center 9 4 and radius square root of 5 x 42 y 92 5 x 92 y 42 5 x 42 y 92 5 x 92 y 42 5 class=

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aimcrey

Answer: The answer is the 4th, [tex](x+9)^{2} +(y+4)^{2} =5[/tex]. When it comes to circle and plugging it into an equation, you flip the signs (I know, the trickery) so if it is positive 9 it would be negative 9 in the equation.

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