Answer:
90.9% is the percent yield of the reaction.
Explanation:
Mass of hydrogen gas = 24.2 g
Moles of hydrogen = [tex]\frac{24.2 g}{2g/mol}=12.1 mol[/tex]
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
According to reaction, 2 moles of hydrogen gas gives 2 moles of water , then 12.1 moles of hydrogen will give:
[tex]\frac{2}{2}\times 12.1mol=12.1mol[/tex] water
Mass of 12.1 moles of water
= 12.1 mol × 18 g/mol = 217.8 g
Theoretical yield of water = 217.8 g
Experimental yield of water = 198 g
The percentage yield of reaction:
[tex]=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
[tex]=\frac{198 g}{217.8 g}\times 100=90.9\%[/tex]
90.9% is the percent yield of the reaction.
