On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 555 every 222222 days, and can be modeled by a function, LLL, which depends on the amount of time, ttt (in days). Before the first day of spring, there were 760076007600 locusts in the population. Write a function that models the locust population ttt days since the first day of spring.

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Answer:

          [tex]L(t)=7600(5)^{t/2}[/tex]

Explanation:

Amend the typos for better understanding:

  • On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 5 every 2 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 7600 locusts in the population. Write a function that models the locust population t days since the first day of spring.

Solution

A function that grows with a constant factor is modeled by an exponential function of the kind:

                                      [tex]F(x)=A\cdot (B)^x[/tex]

Where A is the initial value, B is the constant growing factor, and x is the number of times the growing factor applies.

Since the population increases by a factor of 5 every 2 days, the power x of the exponential function is t/2, and the factor B is 5.

The initial popultaion A is 7600.

Thus, the function that models the locust population t days since the first day of spring is:

             [tex]L(t)=7600(5)^{t/2}[/tex]

Answer: L(t)= 7600 times 5^t/22

Step-by-step explanation:

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