Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration [tex]a=5.56m/sec^2[/tex]
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion [tex]v^2=u^2+2as[/tex]
Putting all values in equation
[tex]278^2=0^2+2\times 5.56\times s[/tex]
s = 6950 m
So distance traveled during this acceleration will be 6950 m
