Answer:
Correct answer: E₁ = 4 · E The electric field increased four times
Explanation:
Given:
E - Electric field at distance d
E₁ - Electric field at distance d₁
Q - Charge of an object
d₁ = (1/2) d
The formula by which the electric field is calculated is:
E = k Q / d²
Electric field at a distance d₁
E₁ = k Q / d₁²
We will form their quotient
E₁ / E = ((k Q) / d₁²) / ((k Q) / d²)
When the constant k and the charge Q is canceled we get:
E₁ / E = (1 / d₁²) / (1 / d²) = d² / d₁² = d² / ((1/2) d)² = 1 /(1/4) = 4
E₁ = 4 · E
The electric field increased four times
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