Respuesta :

zr7929

Answer:

1.5 L of 0.1 M sulfuric acid solution is to be made.

Number of moles of sulfuric acid present in 1.5 L of 0.1 M = Molarity * volume = 0.1* 1.5 = 0.15...

Explanation:

Cricetus

The volume will be "0.15 L".

According to the question,

Molarity,

  • 0.10 M

Volume,

  • 1.5 L

Now,

The volume of the solution,

= [tex]Molarity\times Volume[/tex]

By substituting the values, we get

= [tex]0.1\times 1.5[/tex]

= [tex]0.15 \ L[/tex]

Thus the approach above is correct.

Learn more about sulfuric acid here:

https://brainly.com/question/5851339

Otras preguntas