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I have two bags of counters.
The first bag contains two red counters and one blue counter.
The second bag contains one red counter, one blue counter
and two yellow counters.
I take a counter at random from both bags.
a) What is the probability that the two counters will be the same colour?
b) What is the probability that exactly one of the counters will be red?​

Respuesta :

qox0x0oxooxo7

Answer:

oooooh Mathswatch.a=3/12  b=7/12

Step-by-step explanation:

a=You need to list all the probability out

There is a total of 24 possibility and 6 of them are the same colour. Simplify it, it becomes 3/12

b= see the photo. (sorry the photo wasn't too good, I am on a computer)

There are a total of 14 combination that has one red counter in it, simplify it, it is 7/12

Ver imagen qox0x0oxooxo7

A) The probability that the two counters will be the same colour is; ¼

B) Probability that exactly one of the counters will be red is; P(exactly one counter is red) = 7/12

We are told that he has 2 bags of counters;

First bag;

- 2 red counters

- 1 blue counter

Second bag;

- One red counter

- One blue counter

- two yellow counters

A) He takes a counter from both bags, probability that they will be same colour is;

RR or BB

Now, P(RR) = ⅔ × ¼ = 2/12

P(BB) = ⅓ × ¼ = 1/12

Thus;

P(both same colour) = 2/12 + 1/12

P(both same colour) = ¼

B) Probability that exactly one of the counters will be red;

The possible combinations in this way that have a red is 14.

Meanwhile total possible combinations is 24.

Thus;

P(exactly one counter is red) = 14/24

P(exactly one counter is red) = 7/12

Read more at; https://brainly.com/question/16601588

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