The area of the triangle with vertices X(6,8), Y(3,3), and Z(13,-3) is 34 square units.
Coordinates of vertices are:
X≡(6,8)
Y≡(3,3)
Z≡(13,-3)
The area of a triangle with the above vertices is given by:[tex]\frac{1}{2} [x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]
So the area of the triangle with vertices X(6,8), Y(3,3), and Z(13,-3)
=[tex]\frac{1}{2} [6(3+3)+3(-3-8)+13(8-3)][/tex]
=34 square units.
Hence, the area of the triangle with vertices X(6,8), Y(3,3), and Z(13,-3) is 34 square units.
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