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If a car accelerates uniformly from rest to 15 meters
per second over a distance of 100 meters, the magnitude of the car’s acceleration is

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asuwafohjames

Answer:

1.125 m/s²

Explanation:

Applying Newton's equation of motion,

v² = u²+2as

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

Note: u = 0 m/s ( from rest)

make a the subject of the equation above.

a = v²/2s................ Equation 2

Given: v = 15 m/s². s =  100 m

Substitute into equation 2

a = 15²/(2×100)

a = 225/200

a = 1.125 m/s²

Ritmeks

The magnitude of the car's acceleration is 1.125 m/s²

The calculation can be as follows;

u= 0

v= 15m/s

s= 100 meters

The formular is

v²= u² + 2as

15² = 0² + 2(a)(100)

225= 200a

a= 225/200

a= 1.125

Hence the initial velocity is 1.125 m/s²

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