Answer:
[tex] \mu -2\sigma = 915.428 - 2* 22.87=869.69[/tex]
[tex] \mu +2\sigma = 915.428 + 2* 22.87=961.17[/tex]
And the best option would be:
4. Minimum: 869.69; maximum: 961.17
Step-by-step explanation:
We can assume that the variable of interst X is distributed with a binomial distribution and we can use the normal approximation.
For this case the mean would be given by:
[tex] E(X) = np = 2136 *(\frac{3}{7})= 915.428[/tex]
And the standard deviation would be:
[tex] \sigma = \sqrt{2136*(\frac{3}{7}) (1-\frac{3}{7})} =22.87[/tex]
And if we find the limits we got:
[tex] \mu -2\sigma = 915.428 - 2* 22.87=869.69[/tex]
[tex] \mu +2\sigma = 915.428 + 2* 22.87=961.17[/tex]
And the best option would be:
4. Minimum: 869.69; maximum: 961.17
