A bag contains 5 white, 3 black, and 2 green balls. Balls are picked at random.
Explain why the events picking a black ball and then another black ball are
dependent. Then identify the probability,

Respuesta :

Answer:

look down there

Step-by-step explanation:

First ball:

Probability of drawing a white ball is 5/8

Probability of drawing a black ball is 3/8

Second ball:

This depends on the first ball drawn, lets say you drew a white ball initially, 4 white balls are left out of 7 balls in total. The probability of a white ball in the second pick is 4/7.

Total probability of drawing two white balls is 5/8*4/7 (since they are independent events).

If you picked a black ball initially, picking another black ball would have a probability of 2/7, on similar grounds , total prob for 2 blacks would be 3/8*2/7.

The probability that you pick 2 balls of same color is (5/14 + 3/28) = 13/28. (Since they are mutually exclusive events)

The probability of picking a black ball and then another black ball is; Due to conditional probability and is equal to 1/15

How to solve conditional probability?

Conditonal probability means that the probability of one event is affected or depends on the probability of another event.

Now, total balls in the bag is;

Total balls = 5 + 3 + 2

Total balls = 10 balls

Probability of first picking a black ball is;

P(black ball first) = 3/10

Now, when a black ball is picked, there will ba 9 balls left in the bag of whih only 2 are black. Thus, the probability of picking another black ball is;

P(black ball second) = 2/9

Thus;the probability of picking a black ball and then another black ball is;

P(black ball | black ball) = 3/10 * 2/9

P(black ball | black ball) = 1/15

Read more about Conditional Probability at; https://brainly.com/question/10739997