There is a bag filled with 4 blue, 3 red and 5 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting 2 greens?

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Answer:

The answer would be just about 61% or 9/14

Step-by-step explanation:

So, it would be a 71% chance to get 1 green out of the bag, but then you have to keep that green out, which then lowers the chances of getting another green out of the bag, then you have to combine the percentages, and then that is the final percentage.

The probability of getting 2 greens is 5/31

Probability is the likelihood or chance that an event will occur. It is expressed as:

Probability = Expected outcome/Total outcome

Given that a bag is filled with 4 blue, 3 red and 5 green marbles, the total outcome is expressed as:

  • Total outcome = 4 + 3 + 5 = 12balls

If green is picked at first, the probability of selecting a green is  5/12

  • If the second marble is picked and not replaced, the probabiity that it is green is 4/11 (4 greens remaining)

The probability of getting 2 greens = 5/12 × 4/11

The probability of getting 2 greens = 20/132

The probability of getting 2 greens = 5/31

Hence the probability of getting 2 greens is 5/31

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