Answer: The quantity of pure [tex]MgSO_4[/tex] in 2.4 g of [tex]MgSO_4.7H_2O[/tex] is 1.17 g
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{2.4g}{246g/mol}=0.0098moles[/tex]
As 1 mole of [tex]MgSO_4.7H_2O[/tex] contains = 1 mole of [tex]MgSO_4[/tex]
Thus 0.0098 moles of [tex]MgSO_4.7H_2O[/tex] contains = [tex]\frac{1}{1}\times 0.0098=0.0098mole[/tex] of [tex]MgSO_4[/tex]
Mass of [tex]MgSO_4=0.0098mol\times 120g/mol=1.17g[/tex]
Thus the quantity of pure [tex]MgSO_4[/tex] in 2.4 g of [tex]MgSO_4.7H_2O[/tex] is 1.17 g
