Answer:
2/7
Step-by-step explanation:
Seven employees can be arranged in 7! ways. n(S) = 7!
Two adjacent desks for married couple can be selected in 6 ways viz.,(1, 2), (2, 3), (3,4), (4, 5), (5,6),(6,7).
This couple can be arranged in the two desks in 2! ways. Other five persons can be arranged in 5! ways.
So, number of ways in which married couple occupy adjacent desks
= 6×2! x 5! =2×6!
so, the probability that the married couple will have adjacent desks
[tex]\frac{n(A)}{n(s)} =\frac{2\times6!}{7!} \\=\frac{2}{7}[/tex]
