Answer:
the answer is given below
Step-by-step explanation:
The question is not complete, I would show you how to find the focus of a parabola when given an equation.
A parabola is the locus of a point in which its distance from a fixed point (focus) and a fixed line (directrix) is equal.
The general equation of a parabola in vertex form is given by:
y = a(x - h)² + k
The vertex is (h, k) and the focus is [tex](h,k+\frac{1}{4}a )[/tex]
For example given an equation: 4y = (x - 3)²
4y = (x - 3)²
First we need to divide through by 4, this gives:
4y/4 = (x - 3)²/4
y = (x - 3)²/4
Comparing with The general equation of a parabola in vertex form is given by:
y = a(x - h)² + k
The vertex = (h, k) = (3, 0), the focus is [tex](h,k+\frac{1}{4}a )[/tex] = (3, 1/16)
Answer:
(-2,0)
Step-by-step explanation:
1) the equation you forgot to put was x = -1/8y^2 you donut. So you multiply 8 on both sides to get 8x = -y^2. The vertices are (0,0). make 8 = 4p (from the equation to find p) and you get p=2. since it's -y^2, it's negative so you're gonna go two to the left from the vertices which is (0,0) to find focus. so the focus is gonna be (-2,0).
2) I did the odyssey ware assignment
3) I'm right cuz I said so
