Let
x------> the number of parrot fish
y-------> the number of clown fish
we know that
[tex]\frac{x}{y}= \frac{4}{3}[/tex] ------> equation A
[tex]x=20[/tex]
so
substitute the value of x in the equation A and solve for y
[tex]\frac{20}{y}= \frac{4}{3}\\ \\4*y=20*3 \\ \\y=60/4 \\ \\y=15\ clown\ fish[/tex]
therefore
the answer is
[tex]15\ clown\ fish[/tex]
Answer:
15 clown fish.
Step-by-step explanation:
We have been that Azul went snorkeling and he noticed that the ratio of parrot fish to clown fish was 4:3.
Since proportion states that two fractions are equal, so we will use proportion to solve for our given problem as:
[tex]\frac{\text{Parrot fish}}{\text{Clown fish}}=\frac{4}{3}[/tex]
To find the number of clown fish we will substitute the given number of parrot fish in our equation.
[tex]\frac{20}{\text{Clown fish}}=\frac{4}{3}[/tex]
Upon cross multiplying our equation we will get,
[tex]\text{Clown fish}*4=20*3[/tex]
Upon dividing both sides of our equation by 4 we will get,
[tex]\frac{\text{Clown fish*4}}{4}=\frac{20*3}{4}[/tex]
[tex]\text{Clown fish}=5*3[/tex]
[tex]\text{Clown fish}=15[/tex]
Therefore, Azul have seen 15 clown fish.
