Answer:
Sn²⁺ + Tl³⁺ → Sn⁴⁺ + Tl⁺
Explanation:
The Sn²⁺ is oxidized to Sn⁴⁺. Whereas Tl³⁺ is reduced to Tl⁺. The half-reactions are:
Sn²⁺ → 2e⁻ + Sn⁴⁺ (Oxidation, loosing electrons)
Tl³⁺ + 2e⁻ →Tl⁺ (Reduction, gaining electrons)
The sum of the reactions gives:
Sn²⁺ + Tl³⁺ + 2e⁻ → 2e⁻ + Sn⁴⁺ + Tl⁺
Subtracting the electrons in both sides of the reaction:
Sn²⁺ + Tl³⁺ → Sn⁴⁺ + Tl⁺
