Answer:
Equilateral triangle
Step-by-step explanation:
Given question is incomplete; find the figure for this question attached.
From the figure attached,
A circle M has been given with line segments MJ and ML as radii.
MJ ≅ ML
m(major arc JL) = 300°
Therefore, [tex]m(\widehat{JL})=360-300[/tex] = 60°
And the angle subtended by the arc JL at the center = 60°
m∠JML = 60°
Now in ΔJML,
m(∠JML) + m(∠JLM) + m(∠LJM) = 180°
m(∠JML) + m(∠LJM) + m(∠LJM) = 180°
[m(∠JLM) = m(∠LJM) Opposite angles of radii of a circle measure equal]
60° + 2m(∠LJM) = 180°
m(∠LJM) = [tex]\frac{180-60}{2}[/tex] = 60°
Therefore, m(∠LJM) = m(∠JML) = m(∠JLM) = 60°
ΔJLM will be an equilateral triangle.
